(3x^-3y^2)/(x^-4y^-5)

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Solution for (3x^-3y^2)/(x^-4y^-5) equation: 


D( x )

x = 0

x^-4*y^-5 = 0

x = 0

x = 0

x^-4*y^-5 = 0

x^-4*y^-5 = 0

x^-4*y^-5 = 0 // : y^-5

x^-4 = 0

x należy do O

x in (-oo:0) U (0:+oo)

(3*x^-3*y^2)/(x^-4*y^-5) = 0

3*x*y^7 = 0 // : 3*y^7

x = 0

x in { 0} 

x belongs to the empty set

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